# Chapter 13 Solutions and Their Behavior - Study Questions - Page 505b: 47

$-24.6^{\circ}C$

#### Work Step by Step

Molality: $(52.5\ g\div25.94\ g/mol)\div(306/1000)kg=6.614\ m$ Freezing point depression: $\Delta T_f=iK_fm=2\times-1.86^{\circ}C/m\times 6.614\ m=-24.60^{\circ}C$ Freezing point $-24.6^{\circ}C$

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