Chemistry and Chemical Reactivity (9th Edition)

Published by Cengage Learning
ISBN 10: 1133949649
ISBN 13: 978-1-13394-964-0

Chapter 13 Solutions and Their Behavior - Study Questions - Page 505b: 44



Work Step by Step

Boiling point elevation: $80.34-80.10=0.24^{\circ}C$ Molality: $\Delta T_b=K_bm\rightarrow m=0.24^{\circ}C\div 2.53^{\circ}C/m=0.095\ mol/kg$ Number of moles: $0.095\ mol/kg\times (30.0/1000)kg=2.85\times10^{-3}\ mol$ Molar mass: $0.500\ g\div 2.85\times10^{-3}\ mol=175.69\ g/mol$ Molar mass of empirical formula: $89.11\ g/mol$ Molar mass ratio: $175.69/89.11=1.97\approx 2$ Molecular formula: $2\times empirical\ formula=C_{14}H_{10}$
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