Chapter 13 Solutions and Their Behavior - Study Questions - Page 505b: 27

$1.04\ kg$

Vapor pressure of pure water (Appendix G): $525.8\ mmHg$ Mole fraction of solvent: $457/525.8=0.869$ Mole fraction of solute: $1-0.869=0.131$ Number of moles of water: $2000\ g\div18.015\ g/mol=111.02\ mol$ The number of moles of solute: $0.131=x/(x+111.02)\rightarrow x=16.71\ mol$ Mass of ethylene glycol: $16.71\ mol\times62.07\ g/mol=1037.41\ g=1.04\ kg$