Chemistry and Chemical Reactivity (9th Edition)

Published by Cengage Learning
ISBN 10: 1133949649
ISBN 13: 978-1-13394-964-0

Chapter 13 Solutions and Their Behavior - Study Questions - Page 505b: 42


$178.71\ g/mol$

Work Step by Step

Boiling point elevation: $62.22-61.70=0.52^{\circ}C$ Molality: $\Delta T_b=K_bm\rightarrow 0.52^{\circ} C=3.63^{\circ}C/m\times m\rightarrow m=0.14\ mol/kg$ Number of moles of solute: $0.14\ mol/kg_{solute}=n\div (25.0/1000)kg\rightarrow n=0.0036\ mol$ Molar mass: $0.640\ g\div 0.0036\ mol=178.71\ g/mol$
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