## Chemistry and Chemical Reactivity (9th Edition)

Published by Cengage Learning

# Chapter 13 Solutions and Their Behavior - Study Questions - Page 505b: 30

#### Answer

$100.256^{\circ}C$

#### Work Step by Step

Molality: $(15.0\ g\div60.06\ g/mol)\div 0.500\ kg=0.50\ m$ Boiling Point Elevation: $\Delta T_b=K_b\times m=0.5121^{\circ}C/m\times 0.5\ m=0.256\ ^{\circ}C$ Mixture boiling point: $100.00+0.256=100.256^{\circ}C$

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