Chemistry: A Molecular Approach (3rd Edition)

Published by Prentice Hall
ISBN 10: 0321809246
ISBN 13: 978-0-32180-924-7

Chapter 7 - Sections 7.1-7.6 - Exercises - Problems by Topic - Page 330: 46a

Answer

$8.87\times10^{5} kJ/mol.$

Work Step by Step

Energy of one mole of photons = $hν\times\frac{6.022\times10^{23}}{1 mole} = \frac{hc}{λ}\times\frac{6.022\times10^{23}}{1 mole}$ h = $6.626\times10^{-34}Js$ c = $3.00\times10^{8}ms^{-1}$ λ = 0.135 nm = $0.135\times10^{-9}m$ E = $\frac{6.626\times10^{-34}Js\times3.00\times10^{8}ms^{-1}}{0.135\times10^{-9}m}\times\frac{6.022\times10^{23}}{1 mole}$ = $8.87\times10^{8} J/mol$ = $8.87\times10^{5} kJ/mol.$
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