Chemistry: A Molecular Approach (3rd Edition)

Published by Prentice Hall
ISBN 10: 0321809246
ISBN 13: 978-0-32180-924-7

Chapter 7 - Sections 7.1-7.6 - Exercises - Problems by Topic - Page 330: 40a

Answer

2.992 m

Work Step by Step

ν = 100.2 MHz = $100.2\times10^{6}Hz$ c = $2.997925\times10^{8}ms^{-1}$ λ = $\frac{c}{ν} = \frac{2.997925\times10^{8}ms^{-1}}{100.2\times10^{6}s^{-1}}$ = 2.992m
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