Chemistry: A Molecular Approach (3rd Edition)

Published by Prentice Hall
ISBN 10: 0321809246
ISBN 13: 978-0-32180-924-7

Chapter 7 - Sections 7.1-7.6 - Exercises - Problems by Topic - Page 330: 39a

Answer

$4.738\times10^{14}Hz$

Work Step by Step

λ = 632.8 nm = $632.8\times10^{-9}m$ c = $2.997925\times10^{8}ms^{-1}$ Frequency (ν) = c/λ = $\frac{2.997925\times10^{8}ms^{-1}}{632.8\times10^{-9}m}$ = $4.738\times10^{14}s^{-1}$
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