Chemistry: A Molecular Approach (3rd Edition)

Published by Prentice Hall
ISBN 10: 0321809246
ISBN 13: 978-0-32180-924-7

Chapter 7 - Sections 7.1-7.6 - Exercises - Problems by Topic - Page 330: 44

Answer

$1.1\times10^{21}$ photons.

Work Step by Step

Energy of one photon= $\frac{hc}{\lambda}$ $=\frac{(6.626\times10^{-34}\,Js)(2.99792458\times10^{8}\,m/s)}{6.5\times10^{-6}\,m}$ $=3.056\times10^{-20}\,J$ Number of photons=$ \frac{\text{Total energy}}{\text{Energy of one photon}}$ $=\frac{32.8\,J}{3.056\times10^{-20}\,J}$ $=1.1\times10^{21}$
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