Chemistry: A Molecular Approach (3rd Edition)

Published by Prentice Hall
ISBN 10: 0321809246
ISBN 13: 978-0-32180-924-7

Chapter 7 - Sections 7.1-7.6 - Exercises - Problems by Topic - Page 330: 43

Answer

$1.03\times10^{16}$ photons.

Work Step by Step

Energy of one photon, E = hν = $\frac{hc}{λ}$ ( as ν = $\frac{c}{λ}$) h = $6.626\times10^{-34} Js$ c = $2.997925\times10^{8} ms^{-1}$ λ = 532 nm = $532\times10^{-9}m$ E = $\frac{6.626\times10^{-34} Js\times2.997925\times10^{8} ms^{-1}}{532\times10^{-9}m}$ = $3.73\times10^{-19}J$ Total energy = 3.85 mJ = $3.85\times10^{-3}$ Number of photons = Total energy/Energy of one photon = $\frac{3.85\times10^{-3}J}{3.73\times10^{-19}J}$ = $1.03\times10^{16}$
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