Answer
79.8 kJ/mol
Work Step by Step
Energy of one mole of photons = $hν\times\frac{6.022\times10^{23}}{1 mole} = \frac{hc}{λ}\times\frac{6.022\times10^{23}}{1 mole}$
h = $6.626\times10^{-34}Js$
c = $3.00\times10^{8}ms^{-1}$
λ = 1500 nm = $1500\times10^{-9}m$
E = $\frac{6.626\times10^{-34}Js\times3.00\times10^{8}ms^{-1}}{1500\times10^{-9}m}\times\frac{6.022\times10^{23}}{1 mole}$ = $7.98\times10^{4} J/mol$ = 79.8 kJ/mol.
