Answer
$-267 kJ$$\times\frac{1 mol CH_{4}}{-802.3 kJ}\times\frac{16.0423 CH_{4}}{1 mol CH_{4}}$$=5.34 g$ $CH_{4}$
Work Step by Step
Use the enthalpy of reaction as a conversion factor in order to convert from kilojoules to moles of methane. Then use the molar mass of methane to convert from moles to grams of methane.
