Answer
$4.7\times10^{5}\,J$
Work Step by Step
Heat required(q)=mass(m)$\times$ specific heat capacity(c)$\times$change in temperature($\Delta T$)
But mass=density(d)$\times$ volume(V)
Therefore, q= $d\times V\times c\times\Delta T$
$=(1.0\,g/10^{-3}L)\times(1.50\,L)\times(4.18\,J/g\cdot ^{\circ}C) \times(100-25)^{\circ}C$
$=4.7\times10^{5}\,J$
