Chemistry: A Molecular Approach (3rd Edition)

Published by Prentice Hall
ISBN 10: 0321809246
ISBN 13: 978-0-32180-924-7

Chapter 6 - Sections 6.1-6.10 - Exercises - Problems by Topic - Page 288: 59

Answer

$4.30\times10^{3}$ kJ heat is released.

Work Step by Step

Heat= $177\,mL\times\frac{0.788\,g\, acetone}{1\,mL}\times\frac{1\,mol\, acetone}{58.08\,g\, acetone}\times\frac{-1790\,kJ}{1\,mol\, acetone}$ $=-4.30\times10^{3}\,kJ$ Negative sign indicates that the heat is released and can be neglected. Heat released= $4.30\times10^{3}\,kJ$
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