Chemistry: A Molecular Approach (3rd Edition)

Published by Prentice Hall
ISBN 10: 0321809246
ISBN 13: 978-0-32180-924-7

Chapter 6 - Sections 6.1-6.10 - Exercises - Problems by Topic - Page 288: 48

Answer

$9.5\times10^{4}\,J$

Work Step by Step

q= $m\times c\times\Delta T$ $=1.50\times10^{3}\,g\times(0.84\,J/g\cdot ^{\circ}C) \times(100-25)^{\circ}C$ $=9.5\times10^{4}\,J$
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