Answer
-10.2 kJ
Work Step by Step
$\Delta E=q+w$
But at constant pressure, $\Delta H=q$
Therefore, in this case
$\Delta E= \Delta H+w$
$\implies w=\Delta E-\Delta H=-5084.3\,kJ-(-5074.1\,kJ)=-10.2\,kJ$
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