Answer
-51 J
Work Step by Step
$\Delta V= 0.50\,L=0.50\times10^{-3}\,m^{3}$
$P=1.0\,atm=101325\,Pa=101325\,N/m^{2}$
$w= -P\Delta V=-101325\frac{N}{m^{2}}\times0.50\times10^{-3}m^{3}=-51\,J$
Chemistry: A Molecular Approach (3rd Edition)
by Tro, Nivaldo J.
Published by
Prentice Hall
ISBN 10:
0321809246
ISBN 13:
978-0-32180-924-7
Chapter 6 - Sections 6.1-6.10 - Exercises - Problems by Topic - Page 288: 52
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