Chemistry: A Molecular Approach (3rd Edition)

Published by Prentice Hall
ISBN 10: 0321809246
ISBN 13: 978-0-32180-924-7

Chapter 15 - Sections 15.1-15.12 - Exercises - Problems by Topic - Page 747: 95c

Answer

$CN^-$ acts as a weak base in solution. - $CN^-(aq) + H_2O(l) \lt -- \gt HCN(aq) + OH^-(aq)$

Work Step by Step

1. Protonate this anion, to get its conjugate acid: $CN^- --\gt HCN$ 2. Analyze the protonated compound. - Weak acids have weak bases as conjugate pair. - HCN is a weak acid, therefore, $CN^-$ acts as a weak base. 3. Now that we know that, write the equation where $CN^-$ receives a proton from a water molecule, producing $OH^-$ - $CN^-(aq) + H_2O(l) \lt -- \gt HCN(aq) + OH^-(aq)$
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