## Chemistry (4th Edition)

$[H_3O^+] = 2.51 \times 10^{- 5}M$
1. Calculate the pH. pOH + pH = 14 9.4 + pH = 14 pH = 4.6 2. Find $[H_3O^+]$ $[H_3O^+] = 10^{- 4.6}$ $[H_3O^+] = 2.51 \times 10^{- 5}$