Chemistry (4th Edition)

Published by McGraw-Hill Publishing Company
ISBN 10: 0078021529
ISBN 13: 978-0-07802-152-7

Chapter 16 - Questions and Problems - Page 771: 16.14

Answer

(a) $[OH^-] = 8.84 \times 10^{- 11}$ (b) $[OH^-] = 2.19 \times 10^{- 7}$ (c) $[OH^-] = 1.41 \times 10^{- 4}$ (d) $[OH^-] = 3.19 \times 10^{- 13}$

Work Step by Step

(a) $[H^+] * [OH^-] = Kw = 10^{-14}$ $ 1.13\times 10^{- 4} * [OH^-] = 10^{-14}$ $[OH^-] = \frac{10^{-14}}{ 1.13 \times 10^{- 4}}$ $[OH^-] = 8.84 \times 10^{- 11}$ (b) $[H^+] * [OH^-] = Kw = 10^{-14}$ $ 4.55 \times 10^{- 8} * [OH^-] = 10^{-14}$ $[OH^-] = \frac{10^{-14}}{ 4.55 \times 10^{- 8}}$ $[OH^-] = 2.19 \times 10^{- 7}$ (c) $[H^+] * [OH^-] = Kw = 10^{-14}$ $ 7.05 \times 10^{- 11} * [OH^-] = 10^{-14}$ $[OH^-] = \frac{10^{-14}}{ 7.05 \times 10^{- 11}}$ $[OH^-] = 1.41 \times 10^{- 4}$ (d) $[H^+] * [OH^-] = Kw = 10^{-14}$ $ 3.13 \times 10^{- 2} * [OH^-] = 10^{-14}$ $[OH^-] = \frac{10^{-14}}{ 3.13 \times 10^{- 2}}$ $[OH^-] = 3.19 \times 10^{- 13}$
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