## Chemistry (4th Edition)

$[H_3O^+] = 1.61 \times 10^{- 14}M$
1. Since NaOH is a strong base: $[OH^-] = [NaOH] = 0.62M$ 2. Calculate [$H_3O^+$] using $[OH^-]$ $[OH^-] * [H_3O^+] = Kw = 10^{-14}$ $0.62 * [H_3O^+] = 10^{-14}$ $[H_3O^+] = \frac{10^{-14}}{ 0.62}$ $[H_3O^+] = 1.61 \times 10^{- 14}$