Chemistry (4th Edition)

Published by McGraw-Hill Publishing Company
ISBN 10: 0078021529
ISBN 13: 978-0-07802-152-7

Chapter 16 - Questions and Problems - Page 771: 16.17

Answer

(a) $[H_3O^+] = 2.05 \times 10^{- 11}M$ (b) $[H_3O^+] = 3.07 \times 10^{- 8}M$ (c) $[H_3O^+] = 5.95 \times 10^{- 11}M$ (d) $[H_3O^+] = 2.93 \times 10^{- 1}M$

Work Step by Step

(a) $[OH^-] * [H^+] = Kw = 5.13 \times 10^{-13}$ $ 2.5 \times 10^{- 2} * [H^+] = 5.13 \times 10^{-13}$ $[H^+] = \frac{5.13 \times 10^{-13}}{ 2.5 \times 10^{- 2}}$ $[H^+] = 2.05 \times 10^{- 11}$ (b) $[OH^-] * [H^+] = Kw = 5.13 \times 10^{-13}$ $ 1.67 \times 10^{- 5} * [H^+] = 5.13 \times 10^{-13}$ $[H^+] = \frac{5.13 \times 10^{-13}}{ 1.67 \times 10^{- 5}}$ $[H^+] = 3.07 \times 10^{- 8}$ (c) $[OH^-] * [H^+] = Kw = 5.13 \times 10^{-13}$ $ 8.62 \times 10^{- 3} * [H^+] = 5.13 \times 10^{-13}$ $[H^+] = \frac{5.13 \times 10^{-13}}{ 8.62 \times 10^{- 3}}$ $[H^+] = 5.95 \times 10^{- 11}$ (d) $[OH^-] * [H^+] = Kw = 5.13 \times 10^{-13}$ $ 1.75 \times 10^{- 12} * [H^+] = 5.13 \times 10^{-13}$ $[H^+] = \frac{5.13 \times 10^{-13}}{ 1.75 \times 10^{- 12}}$ $[H^+] = 2.93 \times 10^{- 1}$
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