## Chemistry (4th Edition)

c) -89.2$^{\circ}$C, 183.9 K
Given F = -128.6$^{\circ}$F Substitute this value in the equation, C = $\frac{5}{9}$(F-32) Then, we find C (temperature in $^{\circ}C$) = -89.2$^{\circ}$C To get corresponding Kelvin scale value: Use T= t+ 273 where t is the temperature in $^{\circ}$C , i.e. -89.2.