Chemistry 12th Edition

Published by McGraw-Hill Education
ISBN 10: 0078021510
ISBN 13: 978-0-07802-151-0

Chapter 3 - Mass Relationships in Chemical Reactions - Questions & Problems: 3.78

Answer

18.0 g $O_{2}$

Work Step by Step

$2KClO_{3}$ -> $2KCl+3O_{2}$ mass of $O_{2}$ = $\frac{(46.0g2KClO_{3})\times(3molO_{2})\times(32gO_{2})}{(122.5g2KClO_{3})\times(2mol2KClO_{3})\times(1molO_{2})}$ $\approx$ 18.0244898 g $O_{2}$ = 18.0 g $O_{2}$
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