Answer
$5.6\times10^2$ $g$ $CaO$
Work Step by Step
$2CaCO_{3}+O_{2}$ -> $2CaO+3CO_{2}$
CaCO_{3} CaO
mass of CaO = $\frac{(1\times10^3gCaCO_{3})\times(1molCaCO_{3})\times(2molCaO)\times(56.08gCaO)}{(100.09gCaCO_{3})\times(2molCaCO_{3})\times(1molCaO)}$
$\approx$$5.602597\times10^2gCaO$
= $5.6\times10^2$ $g$ $CaO$
