# Chapter 3 - Mass Relationships in Chemical Reactions - Questions & Problems - Page 110: 3.75

$5.6\times10^2$ $g$ $CaO$

#### Work Step by Step

$2CaCO_{3}+O_{2}$ -> $2CaO+3CO_{2}$ CaCO_{3} CaO mass of CaO = $\frac{(1\times10^3gCaCO_{3})\times(1molCaCO_{3})\times(2molCaO)\times(56.08gCaO)}{(100.09gCaCO_{3})\times(2molCaCO_{3})\times(1molCaO)}$ $\approx$$5.602597\times10^2gCaO$ = $5.6\times10^2$ $g$ $CaO$

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