Chemistry 12th Edition

Published by McGraw-Hill Education
ISBN 10: 0078021510
ISBN 13: 978-0-07802-151-0

Chapter 3 - Mass Relationships in Chemical Reactions - Questions & Problems - Page 110: 3.70


a. $2NaHCO_{3}+O_{2}$ -> $2CO_{2}+Na_{2}CO_{3}+H_{2}O$ b. $39.1$ $g$ $NaHCO_{3}$

Work Step by Step

a. $2NaHCO_{3}+O_{2}$ -> $2CO_{2}+Na_{2}CO_{3}+H_{2}O$ (BALANCE THE EQUATION) b. Mass of $NaGCO_{3}$ = $\frac{(20.5gCO_{2})\times(1molCO_{2})\times(2molNaHCO_{3})\times(84.01gNaHCO_{3})}{(44.01gCO_{2})\times(2molCO_{2})\times(1molNaHCO_{3})}$ $\approx$39.13217... = $39.1$ $g$ $NaHCO_{3}$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.