# Chapter 3 - Mass Relationships in Chemical Reactions - Questions & Problems: 3.76

a. $NH_{4}NO_{3}$ -> $N_{2}O+2H_{2}O$ b. $20g$ $N_{2}O$

#### Work Step by Step

a. $NH_{4}NO_{3}$ -> $N_{2}O+2H_{2}O$ b. mass of $N_{2}O$ = $\frac{(0.46molNH_{4}NO_{3})\times(1molN_{2}O)\times(44.02gN_{2}O)}{(1molNH_{4}NO_{3})\times(1molN_{2}O)}$ $=20g$ $N_{2}O$

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