Chemistry 12th Edition

Published by McGraw-Hill Education
ISBN 10: 0078021510
ISBN 13: 978-0-07802-151-0

Chapter 3 - Mass Relationships in Chemical Reactions - Questions & Problems - Page 110: 3.69


13 million tons

Work Step by Step

$S+O_{2}$->$SO_{2}$ mass of Sulfur (in tons)= $\frac{(26\times10^{12}gSO_{2})\times(1molSO_{2})\times(1molS)\times(32.07GSO_{2})}{(64.07gSO_{2})\times(1molSO_{2})\times(1 molS)}$ = 13 million tons
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