Answer
$$K_P = 5.1 \times 10^{-2}$$
Work Step by Step
1. Write the equilibrium constant expression:
- The exponent of each concentration is equal to its balance coefficient.
$$K_P = \frac{[Products]}{[Reactants]} = \frac{P_{ NO } ^{ 2 }}{P_{ N_2 }P_{ O_2 }}$$
2. Substitute the values and calculate the constant value:
$$K_P = \frac{( 0.050 )^{ 2 }}{( 0.15 )( 0.33 )} = 5.1 \times 10^{-2}$$
