Answer
$$K_{c2} = 2.40 \times 10^{33}$$
Work Step by Step
1. Write the Kc expression for both reactions:
$$K_{c1} = 4.17 \times 10^{-34}= \frac{[H_2][Cl_2]}{[HCl]^2}$$
$$K_{c2} = \frac{[HCl]^2}{[H_2][Cl_2]}$$
2. Invert the second equation:
$$\frac{1}{K_{c2}} = \frac{[H_2][Cl_2]}{[HCl]^2}$$
3. Substituting:
$$\frac{1}{K_{c2}} = 4.17 \times 10^{-34}$$
$$K_{c2} = \frac{1}{4.17 \times 10^{-34}} = 2.40 \times 10^{33}$$
