Chemistry 12th Edition

Published by McGraw-Hill Education
ISBN 10: 0078021510
ISBN 13: 978-0-07802-151-0

Chapter 14 - Chemical Equilibrium - Questions & Problems - Page 656: 14.17

Answer

$$K_p = 1.76 \times 10^{20} $$

Work Step by Step

1. Calculate $\Delta n$ (n is the amount of moles of gases): $$\Delta n = n_{products} - n_{reactants} = 2 - 3 = -1 $$ 2. Convert the temperature to Kelvin: $$T/K = 1273 + 273.15 = 1546.15 $$ 3. Calculate Kp: $$K_p = K_c(RT)^{\Delta n} = ( 2.24 \times 10^{22} )(0.0821 \times 1546.15 )^{ -1 }$$ $$K_p = 1.76 \times 10^{20} $$
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