Trigonometry 7th Edition

Published by Cengage Learning
ISBN 10: 1111826854
ISBN 13: 978-1-11182-685-7

Chapter 6 - Section 6.2 - More on Trigonometric Equations - 6.2 Problem Set - Page 332: 6

Answer

$45^{\circ}, 135^{\circ}$

Work Step by Step

Given $\sqrt 2 \csc\theta= 2$...(1) we have to use the reciprocal identity that $\csc\theta $ in terms of $\sin\theta$ i.e. $\csc\theta = \frac{1}{\sin\theta}$...(2) Substitute (2) in equation (1) we get $\sqrt 2 \frac{1}{\sin\theta}= 2$ $\sqrt 2 = 2\sin\theta$ On dividing both sides by 2 $\frac{\sqrt 2}{2} = \frac{2\sin\theta}{2}$ $\frac{1}{\sqrt 2} = \sin\theta$ Therefore $\theta = 45^{\circ}$ sine function is positive in quadrant 1 and 3 So, $\theta = 45^{\circ}$ or $\theta = 180^{\circ}-45^{\circ}$ $\theta = 45^{\circ}$ or $\theta = 135^{\circ}$
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