Trigonometry 7th Edition

Published by Cengage Learning
ISBN 10: 1111826854
ISBN 13: 978-1-11182-685-7

Chapter 5 - Section 5.3 - Double-Angle Formulas - 5.3 Problem Set - Page 297: 56


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Work Step by Step

$LHS = \csc{\theta} -2 \sin{\theta} =\dfrac{1}{\sin{\theta}} - 2 \sin{\theta}$ $LHS = \dfrac{1}{\sin{\theta}}(1-2\sin^2{\theta})= \dfrac{\cos{2\theta}}{\sin{\theta}}= RHS$
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