Answer
See the steps.
Work Step by Step
$LHS = \csc{\theta} -2 \sin{\theta} =\dfrac{1}{\sin{\theta}} - 2 \sin{\theta}$
$LHS = \dfrac{1}{\sin{\theta}}(1-2\sin^2{\theta})= \dfrac{\cos{2\theta}}{\sin{\theta}}= RHS$
Trigonometry 7th Edition
by McKeague, Charles P.; Turner, Mark D.
Published by
Cengage Learning
ISBN 10:
1111826854
ISBN 13:
978-1-11182-685-7
Chapter 5 - Section 5.3 - Double-Angle Formulas - 5.3 Problem Set - Page 297: 56
Update this answer!
You can help us out by revising, improving and updating this answer.
Update this answerAfter you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.
