Trigonometry 7th Edition

Published by Cengage Learning
ISBN 10: 1111826854
ISBN 13: 978-1-11182-685-7

Chapter 5 - Section 5.3 - Double-Angle Formulas - 5.3 Problem Set - Page 297: 55

Answer

See the steps.

Work Step by Step

$LHS = \cot{\theta} -\tan{\theta} =\dfrac{\cos{\theta}}{\sin{\theta}} - \dfrac{\sin{\theta}}{\cos{\theta}}$ $LHS =\dfrac{\cos^2{\theta}-\sin^2{\theta}}{\sin{\theta} \cos{\theta}} = \dfrac{\cos{2\theta}}{\sin{\theta} \cos{\theta}}$
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