Answer
See the steps.
Work Step by Step
$LHS =(\sin{x} - \cos{x})^2 = $
$$(\sin^2 {x} - 2 \sin{x} \cos{x} + \cos^2{x})$$
$$LHS=(\sin^2 {x}+ \cos^2{x})-2 \sin{x} \cos{x}$$
$$LHS= 1 -\sin{2x} = RHS$$
Trigonometry 7th Edition
by McKeague, Charles P.; Turner, Mark D.
Published by
Cengage Learning
ISBN 10:
1111826854
ISBN 13:
978-1-11182-685-7
Chapter 5 - Section 5.3 - Double-Angle Formulas - 5.3 Problem Set - Page 297: 43
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