Answer
$-\dfrac{1}{2}$
Work Step by Step
$\tan{2A} = \dfrac{2 \tan{A}}{1- \tan^2 {A}}$
$\dfrac{\tan{\dfrac{3\pi}{8}}}{1-\tan^2 \dfrac{3\pi}{8}} = \dfrac{1}{2} \tan{\dfrac{3\pi}{4}}= -\dfrac{1}{2}$
Trigonometry 7th Edition
by McKeague, Charles P.; Turner, Mark D.
Published by
Cengage Learning
ISBN 10:
1111826854
ISBN 13:
978-1-11182-685-7
Chapter 5 - Section 5.3 - Double-Angle Formulas - 5.3 Problem Set - Page 297: 42
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