Answer
$\sin60^{\circ} = 2\sin30^{\circ}\cos30^{\circ}$
Work Step by Step
Given $\sin60^{\circ} = 2\sin30^{\circ}\cos30^{\circ}$
L.H.S
$\sin60^{\circ} = \frac{\sqrt 3}{2}$ ......(1)
R.H.S
$2\sin30^{\circ}\cos30^{\circ} = 2(\frac{1}{2}\times\frac{\sqrt 3}{2})$
$2\sin30^{\circ}\cos30^{\circ} = \frac{\sqrt 3}{2}$ .....(2)
From (1) & (2)
L.H.S = R.H.S
$\sin60^{\circ} = 2\sin30^{\circ}\cos30^{\circ}$
Its True.