Answer
$ \sqrt{3}$
Work Step by Step
$\tan{2A} = \dfrac{2 \tan{A}}{1- \tan^2 {A}}$
$\tan{2A} = \dfrac{2 \times - \sqrt{3}}{1-(-\sqrt{3})^2}$
$\tan{2A} = \sqrt{3}$
You can help us out by revising, improving and updating this answer.
Update this answerAfter you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.