Trigonometry (10th Edition)

Published by Pearson
ISBN 10: 0321671775
ISBN 13: 978-0-32167-177-6

Chapter 8 - Complex Numbers, Polar Equations, and Parametric Equations - Section 8.1 Complex Numbers - 8.1 Exercises - Page 357: 50

Answer

$-3-i\sqrt 2$

Work Step by Step

$\frac{-9-\sqrt -18}{3}=\frac{-9-\sqrt (-9\times2)}{3}=\frac{-9-3i\sqrt 2}{3}=\frac{3(-3-i\sqrt 2)}{3}=-3-i\sqrt 2$ We know that $\sqrt -1=i$, because $i^{2}=-1$.
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