Answer
$i\sqrt 3$
Work Step by Step
$\frac{\sqrt -24}{\sqrt 8}=\frac{i\sqrt 24}{\sqrt 8}=i\times\frac{\sqrt 24}{\sqrt 8}=i\times\sqrt \frac{24}{8}=i\times\sqrt 3=i\sqrt 3$
We know that $\sqrt -1=i$, because $i^{2}=-1$.
Trigonometry (10th Edition)
by Lial, Margaret L.; Hornsby, John; Schneider, David I.; Daniels, Callie
Published by
Pearson
ISBN 10:
0321671775
ISBN 13:
978-0-32167-177-6
Chapter 8 - Complex Numbers, Polar Equations, and Parametric Equations - Section 8.1 Complex Numbers - 8.1 Exercises - Page 357: 43
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