Trigonometry (10th Edition)

Published by Pearson
ISBN 10: 0321671775
ISBN 13: 978-0-32167-177-6

Chapter 8 - Complex Numbers, Polar Equations, and Parametric Equations - Section 8.1 Complex Numbers - 8.1 Exercises - Page 357: 21

Answer

$12i\sqrt 2$

Work Step by Step

$\sqrt -288=\sqrt (144\times2\times-1)=\sqrt 144\times\sqrt 2\times\sqrt -1=12i\sqrt 2$ We know that $\sqrt 144=12$, because $12^{2}=144$. We know that $\sqrt -1=i$, because $i^{2}=-1$.
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