Answer
(a) We can see the point plotted on the graph below.
(b) We can write two pairs of polar coordinates for this point:
$(2, 180^{\circ})$
$(-2, 0^{\circ})$
![](https://gradesaver.s3.amazonaws.com/uploads/solution/0cc5c399-3ba5-4891-83c5-987937e28040/result_image/1529392993.jpg?X-Amz-Algorithm=AWS4-HMAC-SHA256&X-Amz-Credential=AKIAJVAXHCSURVZEX5QQ%2F20240727%2Fus-east-1%2Fs3%2Faws4_request&X-Amz-Date=20240727T051503Z&X-Amz-Expires=900&X-Amz-SignedHeaders=host&X-Amz-Signature=bf29e249e5bdbdc3aa4a8bf2e0d6c60b86f23746be378afe67db242e26a606f3)
Work Step by Step
$(-2, 0)$
(a) We can see the point plotted on the graph below.
(b) $r = \sqrt{(-2)^2+(0)^2} = 2$
Since the point is on the negative x-axis, the angle $\theta = 180^{\circ}$
We can write two pairs of polar coordinates for this point:
$(2, 180^{\circ})$
$(-2, 0^{\circ})$
![](https://gradesaver.s3.amazonaws.com/uploads/solution/0cc5c399-3ba5-4891-83c5-987937e28040/steps_image/small_1529392993.jpg?X-Amz-Algorithm=AWS4-HMAC-SHA256&X-Amz-Credential=AKIAJVAXHCSURVZEX5QQ%2F20240727%2Fus-east-1%2Fs3%2Faws4_request&X-Amz-Date=20240727T051503Z&X-Amz-Expires=900&X-Amz-SignedHeaders=host&X-Amz-Signature=974a03b904de014999b0f6f46b0becf09b8e8b98a51810e3e2620d623e1c478e)