#### Answer

$(1, 1)$
(a) We can see the point plotted on the graph below.
(b) We can write two pairs of polar coordinates for this point:
$(\sqrt{2}, 45^{\circ})$
$(-\sqrt{2}, 225^{\circ})$

#### Work Step by Step

$(1, 1)$
(a) We can see the point plotted on the graph below.
(b) $r = \sqrt{(1)^2+(1)^2} = \sqrt{2}$
We can find the angle $x$ above the positive x-axis:
$tan~x = \frac{1}{1}$
$x = arctan(\frac{1}{1})$
$x = 45^{\circ}$
We can write two pairs of polar coordinates for this point:
$(\sqrt{2}, 45^{\circ})$
$(-\sqrt{2}, 225^{\circ})$