Answer
(a) We can see the point plotted on the graph below.
(b) We can write two pairs of polar coordinates for this point:
$(3, 0^{\circ})$
$(-3, 180^{\circ})$
![](https://gradesaver.s3.amazonaws.com/uploads/solution/40ee5c9d-c30b-4df3-ac5a-088486a1d6dd/result_image/1529392768.jpg?X-Amz-Algorithm=AWS4-HMAC-SHA256&X-Amz-Credential=AKIAJVAXHCSURVZEX5QQ%2F20240727%2Fus-east-1%2Fs3%2Faws4_request&X-Amz-Date=20240727T021210Z&X-Amz-Expires=900&X-Amz-SignedHeaders=host&X-Amz-Signature=a413533276ae55340ddfb43f24c413a67de881bdaa88b13703efd17cac3749a6)
Work Step by Step
$(3, 0)$
(a) We can see the point plotted on the graph below.
(b) $r = \sqrt{(3)^2+(0)^2} = 3$
Since the point is on the positive x-axis, the angle $\theta = 0^{\circ}$
We can write two pairs of polar coordinates for this point:
$(3, 0^{\circ})$
$(-3, 180^{\circ})$
![](https://gradesaver.s3.amazonaws.com/uploads/solution/40ee5c9d-c30b-4df3-ac5a-088486a1d6dd/steps_image/small_1529392768.jpg?X-Amz-Algorithm=AWS4-HMAC-SHA256&X-Amz-Credential=AKIAJVAXHCSURVZEX5QQ%2F20240727%2Fus-east-1%2Fs3%2Faws4_request&X-Amz-Date=20240727T021210Z&X-Amz-Expires=900&X-Amz-SignedHeaders=host&X-Amz-Signature=144c2fdb43a3a5b297dae0f2f6faac67cef1fe3f7932a5e88eeab83dbb4a9331)