## Trigonometry (11th Edition) Clone

(a) We can see the point plotted on the graph below. (b) We can write two pairs of polar coordinates for this point: $(2, 135^{\circ})$ $(-2, 315^{\circ})$
$(-\sqrt{2}, \sqrt{2})$ (a) We can see the point plotted on the graph below. (b) $r = \sqrt{(-\sqrt{2})^2+(\sqrt{2})^2} = 2$ We can find the angle $\phi$ above the negative x-axis: $tan~\phi = \frac{\sqrt{2}}{\sqrt{2}}$ $\phi = arctan(\frac{\sqrt{2}}{\sqrt{2}})$ $\phi = 45^{\circ}$ We can write two pairs of polar coordinates for this point: $(2, 135^{\circ})$ $(-2, 315^{\circ})$