#### Answer

(a) We can see the point plotted on the graph below.
(b) We can write two pairs of polar coordinates for this point:
$(2, 45^{\circ})$
$(-2, 225^{\circ})$

#### Work Step by Step

$(\sqrt{2}, \sqrt{2})$
(a) We can see the point plotted on the graph below.
(b) $r = \sqrt{(\sqrt{2})^2+(\sqrt{2})^2} = 2$
We can find the angle $x$ above the positive x-axis:
$tan~x = \frac{\sqrt{2}}{\sqrt{2}}$
$x = arctan(\frac{\sqrt{2}}{\sqrt{2}})$
$x = 45^{\circ}$
We can write two pairs of polar coordinates for this point:
$(2, 45^{\circ})$
$(-2, 225^{\circ})$