Answer
(a) We can see the point plotted on the graph below.
(b) We can write two pairs of polar coordinates for this point:
$(3, 90^{\circ})$
$(-3, 270^{\circ})$
![](https://gradesaver.s3.amazonaws.com/uploads/solution/4ecaface-88d6-4a15-87f0-2f93507eb0fd/result_image/1529390151.jpg?X-Amz-Algorithm=AWS4-HMAC-SHA256&X-Amz-Credential=AKIAJVAXHCSURVZEX5QQ%2F20240727%2Fus-east-1%2Fs3%2Faws4_request&X-Amz-Date=20240727T013036Z&X-Amz-Expires=900&X-Amz-SignedHeaders=host&X-Amz-Signature=dddcaab7f3f4b1faf528ef5caee40c4be6c761097da7dffc77a660b25f267bce)
Work Step by Step
$(0, 3)$
(a) We can see the point plotted on the graph below.
(b) $r = \sqrt{(0)^2+(3)^2} = 3$
The angle $x$ is $90^{\circ}$ counter-clockwise from the positive x-axis.
We can write two pairs of polar coordinates for this point:
$(3, 90^{\circ})$
$(-3, 270^{\circ})$
![](https://gradesaver.s3.amazonaws.com/uploads/solution/4ecaface-88d6-4a15-87f0-2f93507eb0fd/steps_image/small_1529390151.jpg?X-Amz-Algorithm=AWS4-HMAC-SHA256&X-Amz-Credential=AKIAJVAXHCSURVZEX5QQ%2F20240727%2Fus-east-1%2Fs3%2Faws4_request&X-Amz-Date=20240727T013036Z&X-Amz-Expires=900&X-Amz-SignedHeaders=host&X-Amz-Signature=562b3e62c2e586b463fea4ad502d6c764f182562d696a2786d0cdacd266f083d)