Trigonometry (11th Edition) Clone

Published by Pearson
ISBN 10: 978-0-13-421743-7
ISBN 13: 978-0-13421-743-7

Chapter 6 - Test - Page 293: 7


Since $\frac{5\pi}{6} \gt \frac{\pi}{2}$, then $arcsin(sin~\frac{5\pi}{6}) \neq \frac{5\pi}{6}$

Work Step by Step

$arcsin(sin~\frac{5\pi}{6}) = arcsin(0.5) = \frac{\pi}{6}$ The domain of arcsin is $[-\frac{\pi}{2}, \frac{\pi}{2}]$ Since $\frac{5\pi}{6} \gt \frac{\pi}{2}$, then $arcsin(sin~\frac{5\pi}{6}) \neq \frac{5\pi}{6}$
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