## Trigonometry (11th Edition) Clone

$cos~ (arcsin\frac{2}{3}) = \frac{\sqrt{5}}{3}$
Let $\theta = arcsin\frac{2}{3}$ $sin~\theta = \frac{2}{3} = \frac{opp}{hyp}$ The adjacent side is $\sqrt{3^2-2^2} = \sqrt{5}$ We can find $cos~\theta$: $cos~\theta = \frac{\sqrt{5}}{3}$ Therefore, $cos~ (arcsin\frac{2}{3}) = \frac{\sqrt{5}}{3}$