Trigonometry (11th Edition) Clone

Published by Pearson
ISBN 10: 978-0-13-421743-7
ISBN 13: 978-0-13421-743-7

Chapter 6 - Test - Page 293: 3c



Work Step by Step

RECALL: $y=\cot^{-1}{x}\longrightarrow \cot{y}=x$, and $0 \lt y\lt 180^o$ Thus, $\theta=\cot^{-1}{(-1)}\longrightarrow \cot{\theta}=-1$ The cotangent function is negative in the second and fourth quadrants. Note that $\cot{135^o} = -1$ Therefore, solving the equation above gives $\theta = 135^o$
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